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1544 andrew gelman stats-2012-10-22-Is it meaningful to talk about a probability of “65.7%” that Obama will win the election?


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Introduction: The other day we had a fun little discussion in the comments section of the sister blog about the appropriateness of stating forecast probabilities to the nearest tenth of a percentage point. It started when Josh Tucker posted this graph from Nate Silver : My first reaction was: this looks pretty but it’s hyper-precise. I’m a big fan of Nate’s work, but all those little wiggles on the graph can’t really mean anything. And what could it possibly mean to compute this probability to that level of precision? In the comments, people came at me from two directions. From one side, Jeffrey Friedman expressed a hard core attitude that it’s meaningless to give a probability forecast of a unique event: What could it possibly mean, period, given that this election will never be repeated? . . . I know there’s a vast literature on this, but I’m still curious, as a non-statistician, what it could mean for there to be a meaningful 65% probability (as opposed to a non-quantifiab


Summary: the most important sentenses genereted by tfidf model

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1 The other day we had a fun little discussion in the comments section of the sister blog about the appropriateness of stating forecast probabilities to the nearest tenth of a percentage point. [sent-1, score-0.757]

2 And what could it possibly mean to compute this probability to that level of precision? [sent-4, score-0.328]

3 From one side, Jeffrey Friedman expressed a hard core attitude that it’s meaningless to give a probability forecast of a unique event: What could it possibly mean, period, given that this election will never be repeated? [sent-6, score-0.729]

4 Similarly, I might describe someone as being 5 feet 8 inches tall, or even 5 feet 8 1/2 inches tall, but it would be silly to call him 5 feet 8. [sent-34, score-0.725]

5 One reason is that intrade prices are quoted to 3 digit precision — viz. [sent-38, score-0.399]

6 Nate’s page doesn’t give a standard error, but let’s suppose that his forecast for Obama’s popular vote share is a normal distribution with mean 50. [sent-68, score-0.909]

7 Then the probability Obama will win the popular vote is pnorm((50. [sent-75, score-0.684]

8 A big lead in the probability (65%-35%) corresponds to a liny lead in the vote (50. [sent-82, score-0.756]

9 Now suppose that our popular vote forecast is off by one-tenth of a percentage point. [sent-85, score-0.871]

10 Given all our uncertainties, it would seem pretty ridiculous to claim we could forecast to that precision anyway, right? [sent-86, score-0.401]

11 If we bump Obama’s predicted 2-party vote share up to 50. [sent-87, score-0.439]

12 If we ratchet Obama’s expected vote share down to 50. [sent-92, score-0.555]

13 1% in Obama’s expected vote share corresponds to a change of 2. [sent-98, score-0.771]

14 1 percentage points, then his expected percentage of the two-party vote must be qnorm(0. [sent-105, score-0.749]

15 I can’t see that it can possibly make sense to imagine an election forecast with that level of precision. [sent-112, score-0.41]

16 Even multiplying everything by ten—specifying win probabilities to the nearest percentage point—corresponds to specifying expected vote shares to within 0. [sent-113, score-1.15]

17 Really, I think it would be just fine to specify win probabilities to the nearest 10%, which will register shifts of 0. [sent-115, score-0.437]

18 On the other hand, people want news, hence the pressure to report essentially meaningless statistics such as a change in probability from 65. [sent-125, score-0.343]

19 To see this in another way, imagine that your forecast uncertainty about the election is summarized by 1000 simulations of the election outcome, that is, a 1000 x 51 matrix of simulated vote shares by state. [sent-133, score-0.923]

20 What shift in the vote would carry just 10 out of 1000 simulations over the bar? [sent-137, score-0.452]


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Introduction: The other day we had a fun little discussion in the comments section of the sister blog about the appropriateness of stating forecast probabilities to the nearest tenth of a percentage point. It started when Josh Tucker posted this graph from Nate Silver : My first reaction was: this looks pretty but it’s hyper-precise. I’m a big fan of Nate’s work, but all those little wiggles on the graph can’t really mean anything. And what could it possibly mean to compute this probability to that level of precision? In the comments, people came at me from two directions. From one side, Jeffrey Friedman expressed a hard core attitude that it’s meaningless to give a probability forecast of a unique event: What could it possibly mean, period, given that this election will never be repeated? . . . I know there’s a vast literature on this, but I’m still curious, as a non-statistician, what it could mean for there to be a meaningful 65% probability (as opposed to a non-quantifiab

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Introduction: Michael Axelrod writes: Quantitative historian Allan Lichtman claims to have discovered 13 predictors that determine who will win the popular vote in presidential elections. He predicts Obama will win in 2012. Writing in his New York Times column, “538,” Nate Silver attempted a critique Lichtman’s prediction. Soon afterward Lichtman wrote a rejoinder. Evidently Lichtman has correctly and publicly predicted the popular vote winners in the last 7 presidential elections. I think he predicted Gore would win in 2000. He got the popular vote winner right, but not electoral college vote winner. Lichtman presents his methods in his early 1980s book, “The Keys to the White House.” Lichtman consulted with Volodia Keilis-Borok, and used a kernel discriminant analysis approach on election results from 1860-1980 as the training set. I think there is some argument as to scoring because Lichtman claims more than 7 successes. I guess he divided the data into a training and validation sets and w

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