jmlr jmlr2009 jmlr2009-16 knowledge-graph by maker-knowledge-mining

16 jmlr-2009-Classification with Gaussians and Convex Loss


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Author: Dao-Hong Xiang, Ding-Xuan Zhou

Abstract: This paper considers binary classification algorithms generated from Tikhonov regularization schemes associated with general convex loss functions and varying Gaussian kernels. Our main goal is to provide fast convergence rates for the excess misclassification error. Allowing varying Gaussian kernels in the algorithms improves learning rates measured by regularization error and sample error. Special structures of Gaussian kernels enable us to construct, by a nice approximation scheme with a Fourier analysis technique, uniformly bounded regularizing functions achieving polynomial decays of the regularization error under a Sobolev smoothness condition. The sample error is estimated by using a projection operator and a tight bound for the covering numbers of reproducing kernel Hilbert spaces generated by Gaussian kernels. The convexity of the general loss function plays a very important role in our analysis. Keywords: reproducing kernel Hilbert space, binary classification, general convex loss, varying Gaussian kernels, covering number, approximation

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Summary: the most important sentenses genereted by tfidf model

sentIndex sentText sentNum sentScore

1 Our main goal is to provide fast convergence rates for the excess misclassification error. [sent-5, score-0.209]

2 Allowing varying Gaussian kernels in the algorithms improves learning rates measured by regularization error and sample error. [sent-6, score-0.178]

3 Special structures of Gaussian kernels enable us to construct, by a nice approximation scheme with a Fourier analysis technique, uniformly bounded regularizing functions achieving polynomial decays of the regularization error under a Sobolev smoothness condition. [sent-7, score-0.314]

4 The sample error is estimated by using a projection operator and a tight bound for the covering numbers of reproducing kernel Hilbert spaces generated by Gaussian kernels. [sent-8, score-0.308]

5 Keywords: reproducing kernel Hilbert space, binary classification, general convex loss, varying Gaussian kernels, covering number, approximation 1. [sent-10, score-0.211]

6 Introduction In this paper we study binary classification algorithms generated from Tikhonov regularization schemes associated with general convex loss functions and varying Gaussian kernels. [sent-11, score-0.136]

7 The classifier minimizing the misclassification error is called the Bayes rule fc and is given by fc (x) = 1, if P(y = 1|x) ≥ P(y = −1|x), −1, otherwise. [sent-17, score-0.532]

8 The performance of a classifier C can be measured by the excess misclassification error R (C ) − R ( fc ). [sent-18, score-0.439]

9 X IANG AND Z HOU functions are generated from Tikhonov regularization schemes associated with general convex loss functions and varying Gaussian kernels. [sent-21, score-0.136]

10 Examples of classifying loss functions include the least-square loss φls (t) = (1 − t)2 , the hinge loss φh (t) = (1 −t)+ = max{1 −t, 0} for support vector machine (SVM) algorithms, and the r-norm SVM loss with 1 ≤ r < ∞ defined by φr (t) = (φh (t))r . [sent-23, score-0.253]

11 With the loss φ and Gaussian kernel K σ , the Tikhonov regularization scheme is defined (Wahba, 1990; Evgeniou et al. [sent-26, score-0.163]

12 , 2000; Cristianini and Shawe-Taylor, 2000) with a sample z = {(xi , yi )}m ∈ i=1 φ Z m as the solution fz = fz,σ,λ to the following minimization problem fz = arg min f ∈Hσ 1 m ∑ φ(yi f (xi )) + λ f 2 σ . [sent-27, score-1.254]

13 The purpose of this paper is to estimate the excess misclassification error R (sgn( fz )) − R ( fc ) as m → ∞. [sent-30, score-1.066]

14 Convergence rates will be derived under the choice of the parameters λ = λ(m) = m−γ , σ = σ(m) = λζ = m−γζ (3) for some γ, ζ > 0 and conditions on the distribution ρ and the loss φ. [sent-31, score-0.11]

15 Let us demonstrate our main results by stating learning rates for the least-square loss φ = φls . [sent-35, score-0.11]

16 They are given by means of a Tsybakov noise condition (Tsybakov, 2004) and a function smoothness condition stated in R terms of Sobolev spaces. [sent-37, score-0.156]

17 In general, noise condition (5) does not require smoothness of fρ in domains away from the decision boundary. [sent-59, score-0.127]

18 Note that as t → −∞, the hinge loss φh for the SVM studied in Steinwart and Scovel (2007) increases slowly: φh (t) = O(|t|), while the least-square loss φls in Theorem 1 increases moderately with φls (t) = O(|t|2 ). [sent-60, score-0.114]

19 Difficulty arises for the error analysis with a general loss φ when φ(t) increases fast such as φ = φr with very large r or the exponential-hinge loss we introduce in this paper as φeh (t) = max{e1−t − 1, 0} = e1−t − 1, if t ≤ 1, 0, otherwise. [sent-61, score-0.148]

20 In particular, explicit learning rates will be given in Section 4 for the r-norm SVM loss φr (Theorem 4) and the exponential-hinge loss φeh (Theorem 5). [sent-65, score-0.167]

21 Comparing with Theorem 1, we shall provide at the end of Section 4 an approximation theory viewpoint to the effect of various loss functions for learning algorithm (2): the exponential-hinge loss has some advantages over φls and φr , the r-norm SVM loss φr may have worse performance when r > 2. [sent-66, score-0.195]

22 Two Special Properties of Gaussians and Key Bounds The novelty in our approach for general φ and kernels K σ arises from two special properties of the Gaussian kernels with changing variance σ > 0: nice approximation scheme and low capacity of the RKHS, described in Sections 2. [sent-69, score-0.216]

23 When φ(t) increases fast (as t → −∞), applying the regularizing function fσ,λ in the error analysis (described in Section 2. [sent-78, score-0.108]

24 The first novelty of this paper is to construct a function fσ,λ (which plays the role of a regularizing function in an error decomposition approach discussed in subsection 2. [sent-80, score-0.135]

25 The construction of the explicit approximation scheme for fσ,λ φ is done under a Sobolev smoothness condition of a measurable function fρ minimizing E φ , that is, for a. [sent-85, score-0.141]

26 This shows difficulty in choosing fσ,λ and demonstrates novelty in choosing the function fσ,λ from Theorem 2 for the error analysis with a general loss φ. [sent-96, score-0.118]

27 2 Error Decomposition and Projection Operator The excess misclassification error R (sgn( f )) − R ( fc ) for the classifier sgn( f ) can be bounded by φ means of the excess generalization error E φ ( f )) − E φ ( fρ ) according to some comparison theorems (Zhang, 2004; Chen et al. [sent-99, score-0.629]

28 For example, it was proved in Zhang (2004) that for φ = φh and any measurable function f : X → R, we have R (sgn( f )) − R ( fc ) ≤ E φh ( f ) − E φh ( fc ). [sent-102, score-0.519]

29 (2006) that for some cφ > 0, φ R (sgn( f )) − R ( fc ) ≤ cφ E φ ( f ) − E φ ( fρ ). [sent-105, score-0.249]

30 (12) For the least square loss and ρ satisfying the Tsybakov noise condition, a comparison theorem improving (12) will be given in Section 4 and will be used to prove Theorem 1. [sent-106, score-0.159]

31 Then we can use (12) with f = π( fz ) to bound the excess misclasφ sification error R (sgn( fz ))− R ( fc ) by means of the excess generalization error E φ (π( fz ))− E φ ( fρ ) which in turn can be estimated by an error decomposition technique (Wu and Zhou, 2006). [sent-113, score-2.579]

32 Lemma 1 Let φ be a classifying loss, fz be defined by (2) and fσ,λ ∈ Hσ . [sent-116, score-0.652]

33 Then φ E φ (π( fz )) − E φ ( fρ ) ≤ D (σ, λ) + Sz ( fσ,λ ) − Sz (π( fz )), (13) where the quantity Sz ( f ) is defined for f ∈ C(X) by φ φ Sz ( f ) = [Ezφ ( f ) − Ezφ ( fρ )] − [E φ ( f ) − E φ ( fρ )]. [sent-117, score-1.254]

34 When we use the regularizing function fσ,λ given in Theorem 2, the bound (10) deals with D (σ, λ), the first term of (13). [sent-118, score-0.109]

35 The crucial remaining term Sz (π( fz )) of (13) involves the set of functions { fz }z∈Z m and can be treated by various empirical process techniques such as Rademacher average and entropy integral. [sent-120, score-1.254]

36 Here we use the specialty of the Gaussians that the RKHS has low capacity, hence the last term of (13) can be estimated efficiently and simply by means of covering numbers. [sent-121, score-0.139]

37 Definition 4 For a subset S of C(X) and η > 0, the covering number N (S, η) is the minimal integer l ∈ N such that there exist l disks with radius η covering S. [sent-124, score-0.206]

38 The covering numbers of the unit ball B1 (Cs (X)) of the space Cs (X) has the asymptotic behavior 1 1 c′ ( )n/s ≤ log N (B1 (Cs (X)), η) ≤ c′′ ( )n/s , s s η η 1452 (14) C LASSIFICATION WITH G AUSSIANS where the positive constants c′ , and c′′ are independent of 0 < η < 1. [sent-127, score-0.234]

39 In particular, since a Gaussian s s 1 ′′ 1 kernel K σ is C∞ , an embedding result from Zhou (2003) tells us that log N (B1 , η) ≤ Cs ( η )n/s ( σ )2n ′′ where s > 0 can be arbitrarily large but the constant Cs depends on s. [sent-128, score-0.182]

40 A crucial improved 1 1 bound for the covering number of B1 was given in Zhou (2002) with ( η )n/s replaced by (log η )n+1 as follows. [sent-130, score-0.138]

41 Proposition 1 There exists a constant C0 > 0 depending only on X and n such that 1 1 log N (B1 , η) ≤ C0 (log )n+1 + 2(n+1) η σ ∀ 0 < η < 1, 0 < σ ≤ 1. [sent-131, score-0.104]

42 Bound (15) is almost sharp in the ′ sense that for some C0 > 0 given in Zhou (2003), 1 1 ′ log N (B1 , η) ≥ C0 (log )n/2 + n . [sent-133, score-0.104]

43 This enables us to derive efficient error bounds for the algorithm (2) involving Gaussian kernels, by a simple covering number argument without other empirical process techniques or iteration techniques used in Steinwart and Scovel (2007) and Wu et al. [sent-135, score-0.158]

44 2 2 log , δ (16) (17) where C2 is the constant independent of m, λ, σ or δ. [sent-141, score-0.104]

45 4 Key Bounds We are in a position to present our key bounds for the excess generalization error E φ (π( fz )) − φ E φ ( fρ ) which will be used to get rates for the excess misclassification error R (sgn( fz )) − R ( fc ). [sent-143, score-1.957]

46 q For φ = φh , we can take τ = 0, and an improved power τ = q+1 if the Tsybakov noise condition (5) is satisfied (Steinwart and Scovel, 2007; Wu and Zhou, 2005). [sent-148, score-0.11]

47 Theorem 3 Let σ = λζ and λ = m−γ for some 0 < ζ < 1 and 0 < γ < n some s > 0, then for any 0 < δ < 1, with confidence 1 − δ we have φ E φ (π( fz )) − E φ ( fρ ) ≤ Cm−θ log where θ = min sζγ, γ(1 − nζ), and C is a constant independent of m and δ. [sent-150, score-0.731]

48 1 Proof of Lemma 1 Write the regularized excess generalization error as φ E φ (π( fz )) − E φ ( fρ ) + λ fz + Ezφ (π( fz )) + λ fz 2 Hσ φ 2 Hσ = E φ (π( fz )) − Ez (π( fz )) φ − Ez ( fσ,λ ) + λ fσ,λ 2 σ H φ φ + Ez ( fσ,λ ) − E φ ( fσ,λ ) + E φ ( fσ,λ ) − E φ ( fρ ) + λ fσ,λ 2 σ . [sent-156, score-3.952]

49 This in connection with the definition of fz tells us that the second term on the right-hand side above is at most zero. [sent-159, score-0.668]

50 By φ φ subtracting and adding E φ ( fρ ) in the first and third terms we see E φ (π( fz )) − E φ ( fρ ) is bounded as in (13). [sent-160, score-0.627]

51 φ Let us turn to estimate E φ (π( fz )) − E φ ( fρ ) by (13). [sent-162, score-0.627]

52 For any 0 < δ < 1, with confidence 1 − 2 , the term Sz ( fσ,λ ) of (13) can be bounded as Sz ( fσ,λ ) ≤ 2( φ C[−B,B] +C1 ) log 2 − 1 φ m 2−τ + E φ ( fσ,λ ) − E φ ( fρ ). [sent-166, score-0.104]

53 Solving the quadratic equation for ε by setting the above probability bound to be δ/2, we see that with confidence at least 1 − δ/2, 4 φ 1 m ∑ ξ(zi ) − E(ξ) ≤ m i=1 2 C[−B,B] log δ 3m + 2mσ2 (ξ) log 2 δ m . [sent-172, score-0.243]

54 This in connection with Young’s inequality implies 2mσ2 (ξ) log 2 δ m ≤ 2 log 2 C1 (E(ξ))τ τ 2 log 2 C1 δ δ ≤ (1 − ) m 2 m 1 2−τ τ + E(ξ). [sent-174, score-0.333]

55 2 Therefore, with confidence at least 1 − δ/2, 4 φ 1 m ∑ ξ(zi ) − E(ξ) ≤ m i=1 2 C[−B,B] log δ 3m 2 log 2 C1 δ m + 1 2−τ + E(ξ). [sent-175, score-0.208]

56 1 The sample error term −Sz (π( fz )) in (13) can be expressed as ξz dρ − m ∑m ξz (zi ) with i=1 φ ξz (z) = φ(y fz (x)) − φ(y fρ (x)). [sent-177, score-1.288]

57 Here we use the specialty of low capacity of the RKHS Hσ and overcome the difficulty by a simple covering number argument over a ball of Hσ where fz lies. [sent-180, score-0.827]

58 The proof follows easily by taking f = 0 in the definition of fz as in De Vito et al. [sent-182, score-0.627]

59 , 2007; Yao, 2008; Ying, 2007) with covering numbers for the ball { f ∈ Hσ : f Hσ ≤ φ(0)/λ} of the RKHS Hσ , we find the following bound. [sent-189, score-0.13]

60 For any 0 < δ < 1, with confidence at least 1 − δ, we have φ E φ (π( fz )) − E φ ( fρ ) ≤ 4D (σ, λ) + 40ε∗ (m, λ, σ, δ/2) + 4( φ C[−B,B] +C1 ) log 2 − 1 m 2−τ . [sent-195, score-0.731]

61 δ δ Proof Applying Lemma 3, we know that there is a subset V1 of Z m with measure at least 1 − 2 such that for z ∈ V1 , 1 2 Sz ( fσ,λ ) ≤ 2( φ C[−B,B] +C1 ) log m− 2−τ + D (σ, λ). [sent-196, score-0.126]

62 1 Adding the above two bounds and observing that 0 ≤ τ ≤ 1 implies 1−τ/2 ≤ 2 we know from Lemma 1 that for z ∈ V1 ∩V2 , ≤ 1− φ E φ (π( fz )) − E φ ( fρ ) ≤ 4D (σ, λ) + 40ε∗ (m, λ, σ, δ/2) + 4( φ C[−B,B] +C1 ) log 2 − 1 m 2−τ . [sent-199, score-0.774]

63 Deriving Learning Rates In this section we apply Theorem 3 to derive learning rates with various loss functions. [sent-208, score-0.11]

64 Proposition 3 If φ = φls and ρ satisfies noise condition (5) for some q ∈ [0, ∞], then for every measurable function f : X → R, we have q − q+2 E φls ( f ) − E φls ( fρ ) R (sgn( f )) − R ( fc ) ≤ 2Cq q+1 q+2 . [sent-210, score-0.326]

65 Proof Denote X f = {x ∈ X : sgn( f )(x) = fc (x)}. [sent-211, score-0.249]

66 It is known that R (sgn( f ))− R ( fc ) = See, for example, Equation (9. [sent-212, score-0.249]

67 Let us derive learning rates with the r-norm SVM loss φ = φr (1 < r < ∞) for which we have (Chen et al. [sent-231, score-0.11]

68 Then for any 0 < δ < 1, with confidence 1 − δ, we have R (sgn( fz )) − R ( fc ) ≤ Cρ,r m−θr log 2 δ with θr = s 2(s+2n+2) , s 4(s(1−1/r)+n+1) , if 1 < r ≤ 2, if 2 < r < ∞. [sent-236, score-0.98]

69 (22) Proof The convexity of φr gives the variancing power (Bartlett et al. [sent-237, score-0.112]

70 This bound for the excess generalization error together with comparison relation (12) caused by φ′′ (0) = r(r − 1) > 0 yields the desired bound r (22) for the excess misclassification error with the constant Cρ,r = cφr C. [sent-241, score-0.45]

71 2ζ(n+1) φ When φ = φeh , a simple computation shows that the function fρ is given by   1 log 1+ fρ (x) , if − (e2 − 1)/(e2 + 1) ≤ fρ (x) ≤ (e2 − 1)/(e2 + 1),  2 1− fρ (x) φ fρ eh (x) = 1, if fρ (x) > (e2 − 1)/(e2 + 1),   −1, if fρ (x) < −(e2 − 1)/(e2 + 1). [sent-244, score-0.307]

72 Then for any 0 < δ < 1, with confidence 1 − δ, we have R (sgn( fz )) − R ( fc ) ≤ Cρ,eh m−θeh log 2 δ with θeh = s . [sent-248, score-0.98]

73 When s ≤ 1, the same φ condition for fρ implies assumption (8) of fρ eh needed for Theorem 5, as seen from expression (23). [sent-257, score-0.232]

74 It is possible to refine learning rates (22) and (24) by improving comparison relation (12) when Tsybakov noise condition (5) is satisfied. [sent-258, score-0.13]

75 We know from Smale and Zhou (2003) that when φ = φls the approximation error and hence learning rates can essentially be characterized by regularities of the function fρ . [sent-265, score-0.133]

76 However, the index s in regularity assumption φ (8) for the function fρ might vary dramatically, leading to varying power index θ for the learning rates. [sent-268, score-0.123]

77 The dependence of the function fρ eh on fρ has an advantage of ignoring any irregularity appearing in the domain where | fρ (x)| > (e2 − 1)/(e2 + 1). [sent-270, score-0.203]

78 This can be φ seen from the following example where fρ has a singularity at 0 while fρ eh ≡ 1 is C∞ . [sent-271, score-0.227]

79 So regularity assumption (8) is satisfied for φ Sobolev space H ls 2 if and only if s < α + 1 . [sent-274, score-0.284]

80 Then from Theorem 1, we see the learning rate R (sgn( fz )) − R ( fc ) = 2 s O(m−θls log 2 ) with θls = s+2+2 arbitrarily close to 1+2α < 1 . [sent-275, score-1.006]

81 However, for the exponential-hinge 9+2α 8 δ φ loss φeh , we have fρ eh ≡ 1 which follows from expression (23) and the definition fρ (x) = 1 − 1 |x|α ≥ 5 1459 X IANG AND Z HOU 1 1 − 5 > (e2 − 1)/(e2 + 1) on X. [sent-276, score-0.26]

82 Therefore, regularity assumption (8) is satisfied for an arbitrarily large s and Theorem 5 yields the learning rate R (sgn( fz )) − R ( fc ) = O(m−θeh log 2 ) with θeh arbiδ trarily close to 1 . [sent-277, score-1.036]

83 Then Theorem 4 yields the 2 s learning rate R (sgn( fz )) − R ( fc ) = O(m−θr log 2 ) with θr = 4(s(1−1/r)+1+1) arbitrarily close to δ This power index is always less than that of φls or φeh . [sent-284, score-1.059]

84 If X is a connected compact C∞ submanifold of n without boundary and its dimension is d ≤ n, then the covering number estimate (15) holds R with n replaced by the manifold dimension d. [sent-291, score-0.128]

85 Learning rates in Theorems 1, 4 and 5 can be improved with n replaced by d if approximation error estimates similar to Theorem 2 can be established in the manifold setting. [sent-293, score-0.136]

86 In our analysis we assume that the convex loss φ has a zero which excludes the logistic loss φ(t) = log(1 + e−t ). [sent-303, score-0.114]

87 One might generalize our analysis to get some error bounds for the scheme with loss functions without zero by using a general projection operator πM with level M > 0 given by  if f (x) > M,  M −M if f (x) < −M, πM ( f )(x) =  f (x) if − M ≤ f (x) ≤ M. [sent-304, score-0.175]

88 This bound in connection with (30) and (31) implies (26) with the constant B given by φ ′ B = max Cs f˜ρ φ f˜ρ ′ 2 L∞ (Rn ) , (Cs ) n 2 −2 , L2 (Rn ) (2π) φ ′ sup {|φ′ (ξ)| : |ξ| ≤ (Cs + 1) f˜ρ + φ (2) Without the condition f˜ρ ∈ L∞ (Rn ), we bound fσ,λ f˜σ . [sent-339, score-0.141]

89 With this estimate, under Tsybakov noise condition (5), learning rates are obtained in Steinwart and Scovel (2007). [sent-356, score-0.13]

90 For example, when α > q+2 , for an arbitrarily small ε > 0, 2q with confidence 1 − δ, 4 log δ R (sgn( fz )) − R ( fc ) ≤ Cε 2 1 m 2α(q+1) 2α(q+2)+3q+4 −ε . [sent-357, score-1.006]

91 (33) φ Since no Sobolev smoothness is assumed for fρ h = fc (Wahba, 1990), we need to use the regularizing function fσ,λ defined by (7) and derive by some detailed computations that with confidence 1 − δ, (q+1)αn 4 1 (q+2)αn+2(q+1)(n+1) . [sent-358, score-0.373]

92 R (sgn( fz )) − R ( fc ) ≤ Cρ,h log δ m This rate is slightly worse than (33), though the estimate for the confidence is slightly better. [sent-359, score-0.98]

93 Role of Tight Bounds for Covering Numbers In this appendix we prove Lemma 2 which shows a special role of the tight bound (15) for covering numbers concerning Gaussian kernels. [sent-362, score-0.185]

94 + 1464 , C LASSIFICATION WITH G AUSSIANS Proof Observe from (15) that as a function on (0, +∞), the logarithm of the middle term of (16) is bounded by φ(0)|φ′ (−1)| n+1 1 √ + h(ε) := C0 log + 2(n+1) − g(ε), σ λε where g is the strictly increasing function on (0, ∞) defined by g(ε) = mε2−τ . [sent-366, score-0.104]

95 2C1 + 2 φ(−1)ε1−τ 3 Set φ(0)|φ′ (−1)| √ + + λm∆ B = + C0 4C1 (log 2 + σ2(n+1) ) + 4C0C1 (∆ log m)n+1 δ 1 2−τ m 4φ(−1) 2 C0 log + 2(n+1) +C0 (∆ log m)n+1 . [sent-367, score-0.312]

96 3m δ σ 2 If 3 φ(−1)B 1−τ ≤ 2C1 , then g(B ) ≥ 2 C0 mB 2−τ ≥ log + 2(n+1) +C0 (∆ log m)n+1 . [sent-368, score-0.208]

97 4C1 δ σ 2 If 3 φ(−1)B 1−τ > 2C1 , then g(B ) ≥ mB 2−τ 4 1−τ 3 φ(−1)B = mB 4 3 φ(−1) 2 C0 ≥ log + 2(n+1) +C0 (∆ log m)n+1 . [sent-369, score-0.208]

98 δ σ Thus in either case we have C0 2 g(B ) ≥ log + 2(n+1) +C0 (∆ log m)n+1 . [sent-370, score-0.208]

99 It folOn the other hand, since B ≥ , we also see that log ∆ λm B λ lows that 2 δ h(B ) ≤ C0 (∆ log m)n+1 − log −C0 (∆ log m)n+1 = log . [sent-372, score-0.52]

100 Then we know from the special form (3) of λ and σ that ε∗ (m, λ, σ, δ/2) ≤ C2 log 2 δ m 1 2−τ + 1 m 1−2γζ(n+1) 2−τ 1465 + (log m)n+1 m 1 2−τ + φ(0) m . [sent-380, score-0.126]


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