nips nips2003 nips2003-98 knowledge-graph by maker-knowledge-mining

98 nips-2003-Kernel Dimensionality Reduction for Supervised Learning


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Author: Kenji Fukumizu, Francis R. Bach, Michael I. Jordan

Abstract: We propose a novel method of dimensionality reduction for supervised learning. Given a regression or classification problem in which we wish to predict a variable Y from an explanatory vector X, we treat the problem of dimensionality reduction as that of finding a low-dimensional “effective subspace” of X which retains the statistical relationship between X and Y . We show that this problem can be formulated in terms of conditional independence. To turn this formulation into an optimization problem, we characterize the notion of conditional independence using covariance operators on reproducing kernel Hilbert spaces; this allows us to derive a contrast function for estimation of the effective subspace. Unlike many conventional methods, the proposed method requires neither assumptions on the marginal distribution of X, nor a parametric model of the conditional distribution of Y . 1

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Summary: the most important sentenses genereted by tfidf model

sentIndex sentText sentNum sentScore

1 edu Abstract We propose a novel method of dimensionality reduction for supervised learning. [sent-9, score-0.387]

2 Given a regression or classification problem in which we wish to predict a variable Y from an explanatory vector X, we treat the problem of dimensionality reduction as that of finding a low-dimensional “effective subspace” of X which retains the statistical relationship between X and Y . [sent-10, score-0.551]

3 We show that this problem can be formulated in terms of conditional independence. [sent-11, score-0.175]

4 To turn this formulation into an optimization problem, we characterize the notion of conditional independence using covariance operators on reproducing kernel Hilbert spaces; this allows us to derive a contrast function for estimation of the effective subspace. [sent-12, score-0.748]

5 Unlike many conventional methods, the proposed method requires neither assumptions on the marginal distribution of X, nor a parametric model of the conditional distribution of Y . [sent-13, score-0.316]

6 1 Introduction Many statistical learning problems involve some form of dimensionality reduction. [sent-14, score-0.194]

7 The goal may be one of feature selection, in which we aim to find linear or nonlinear combinations of the original set of variables, or one of variable selection, in which we wish to select a subset of variables from the original set. [sent-15, score-0.146]

8 Motivations for such dimensionality reduction include providing a simplified explanation and visualization for a human, suppressing noise so as to make a better prediction or decision, or reducing the computational burden. [sent-16, score-0.416]

9 We study dimensionality reduction for supervised learning, in which the data consists of (X, Y ) pairs, where X is an m-dimensional explanatory variable and Y is an -dimensional response. [sent-17, score-0.486]

10 We refer to these problems generically as “regression,” which indicates our focus on the conditional probability density pY |X (y|x). [sent-19, score-0.175]

11 We wish to solve a problem of feature selection in which the features are linear combinations of the components of X. [sent-21, score-0.105]

12 In particular, we assume that there is an r-dimensional subspace S ⊂ Rm such that the following equality holds for all x and y: (1) pY |X (y|x) = pY |ΠS X (y|ΠS x), where ΠS is the orthogonal projection of Rm onto S. [sent-22, score-0.255]

13 The subspace S is called the effective subspace for regression. [sent-23, score-0.427]

14 We approach the problem within a semiparametric statistical framework—we make no assumptions regarding the conditional distribution pY |ΠS X (y|ΠS x) or the distribution pX (x) of X. [sent-25, score-0.269]

15 Having found an effective subspace, we may then proceed to build a parametric or nonparametric regression model on that subspace. [sent-26, score-0.172]

16 Thus our approach is an explicit dimensionality reduction method for supervised learning that does not require any particular form of regression model; it can be used as a preprocessor for any supervised learner. [sent-27, score-0.502]

17 Most conventional approaches to dimensionality reduction make specific assumptions regarding the conditional distribution pY |ΠS X (y|ΠS x), the marginal distribution pX (x), or both. [sent-28, score-0.651]

18 For example, classical two-layer neural networks can be seen as attempting to estimate an effective subspace in their first layer, using a specific model for the regressor. [sent-29, score-0.268]

19 Similar comments apply to projection pursuit regression [1] and ACE [2], which assume T T an additive model E[Y |X] = g1 (β1 X) + · · · + gK (βK X). [sent-30, score-0.132]

20 While canonical correlation analysis (CCA) and partial least squares (PLS, [3]) can be used for dimensionality reduction in regression, they make a linearity assumption and place strong restrictions on the allowed dimensionality. [sent-31, score-0.362]

21 The line of research that is closest to our work is sliced inverse regression (SIR, [4]) and related methods including principal Hessian directions (pHd, [5]). [sent-32, score-0.125]

22 SIR is a semiparametric method that can find effective subspaces, but only under strong assumptions of ellipticity for the marginal distribution pX (x). [sent-33, score-0.259]

23 If these assumptions do not hold, there is no guarantee of finding the effective subspace. [sent-35, score-0.149]

24 In this paper we present a novel semiparametric method for dimensionality reduction that we refer to as Kernel Dimensionality Reduction (KDR). [sent-36, score-0.389]

25 KDR is based on a particular class of operators on reproducing kernel Hilbert spaces (RKHS, [6]). [sent-37, score-0.312]

26 In distinction to algorithms such as the support vector machine and kernel PCA [7, 8], KDR cannot be viewed as a “kernelization” of an underlying linear algorithm. [sent-38, score-0.118]

27 Rather, we relate dimensionality reduction to conditional independence of variables, and use RKHSs to provide characterizations of conditional independence and thereby design objective functions for optimization. [sent-39, score-0.951]

28 This builds on the earlier work of [9], who used RKHSs to characterize marginal independence of variables. [sent-40, score-0.2]

29 Our characterization of conditional independence is a significant extension, requiring rather different mathematical tools—the covariance operators on RKHSs that we present in Section 2. [sent-41, score-0.47]

30 1 Kernel method of dimensionality reduction for regression Dimensionality reduction and conditional independence The problem discussed in this paper is to find the effective subspace S defined by Eq. [sent-44, score-1.1]

31 sample {(Xi , Yi )}n , sampled from the conditional probability Eq. [sent-48, score-0.175]

32 The crux of the problem is that we have no a priori knowledge of the regressor, and place no assumptions on the conditional probability pY |X or the marginal probability pX . [sent-50, score-0.271]

33 We do not address the problem of choosing the dimensionality r in this paper—in practical applications of KDR any of a variety of model selection methods such as cross-validation can be reasonably considered. [sent-51, score-0.242]

34 Rather our focus is on the problem of finding the effective subspace for a given choice of dimensionality. [sent-52, score-0.268]

35 The notion of effective subspace can be formulated in terms of conditional independence. [sent-53, score-0.443]

36 Let Q = (B, C) be an m-dimensional orthogonal matrix such that the column vectors of B span the subspace S (thus B is m × r and C is m × (m − r)), and define U = B T X and V = C T X. [sent-54, score-0.203]

37 (2) Y Y Y V X U X V |U X = (U,V) Figure 1: Graphical representation of dimensionality reduction for regression. [sent-58, score-0.335]

38 This shows that the effective subspace S is the one which makes Y and V conditionally independent given U (see Figure 1). [sent-59, score-0.268]

39 Mutual information provides another viewpoint on the equivalence between conditional independence and the effective subspace. [sent-60, score-0.402]

40 (1) implies I(Y, X) = I(Y, U ), the effective subspace S is characterized as the subspace which retains the entire mutual information between X and Y , or equivalently, such that I(Y |U, V |U ) = 0. [sent-63, score-0.56]

41 This is again the conditional independence of Y and V given U . [sent-64, score-0.293]

42 2 Covariance operators on kernel Hilbert spaces and conditional independence We use cross-covariance operators [10] on RKHSs to characterize the conditional independence of random variables. [sent-66, score-0.939]

43 Let (H, k) be a (real) reproducing kernel Hilbert space of functions on a set Ω with a positive definite kernel k : Ω × Ω → R and an inner product ·, · H . [sent-67, score-0.266]

44 The most important aspect of a RKHS is the reproducing property: f, k(·, x) H = f (x) for all x ∈ Ω and f ∈ H. [sent-68, score-0.076]

45 (4) In this paper we focus on the Gaussian kernel k(x1 , x2 ) = exp − x1 − x2 2 /2σ 2 . [sent-69, score-0.095]

46 Let (H1 , k1 ) and (H2 , k2 ) be RKHSs over measurable spaces (Ω1 , B1 ) and (Ω2 , B2 ), respectively, with k1 and k2 measurable. [sent-70, score-0.147]

47 (5) implies that the covariance of f (X) and g(Y ) is given by the action of the linear operator ΣY X and the inner product. [sent-73, score-0.135]

48 Under the assumption that EX [k1 (X, X)] and EY [k2 (Y, Y )] are finite, by using Riesz’s representation theorem, it is not difficult to see that a bounded operator ΣY X is uniquely defined by Eq. [sent-74, score-0.077]

49 Cross-covariance operators provide a useful framework for discussing conditional probability and conditional independence, as shown by the following theorem and its corollary1 : Theorem 1. [sent-79, score-0.506]

50 Let (H1 , k1 ) and (H2 , k2 ) be RKHSs on measurable spaces Ω1 and Ω2 , respectively, with k1 and k2 measurable, and (X, Y ) be a random vector on Ω1 ×Ω2 . [sent-80, score-0.147]

51 Assume that EX [k1 (X, X)] and EY [k2 (Y, Y )] are finite, and for all g ∈ H2 the conditional expectation EY |X [g(Y ) | X = ·] is an element of H1 . [sent-81, score-0.199]

52 (8) This can be understood by analogy to the conditional expectation of Gaussian random variables. [sent-94, score-0.199]

53 If X and Y are Gaussian random variables, it is well-known that the conditional expectation is given by EY |X [aT Y | X = x] = xT Σ−1 ΣXY a for an arbitrary vector a, XX where ΣXX and ΣXY are the variance-covariance matrices in the ordinary sense. [sent-95, score-0.199]

54 Using cross-covariance operators, we derive an objective function for characterizing conditional independence. [sent-96, score-0.205]

55 Let (H1 , k1 ) and (H2 , k2 ) be RKHSs on measurable spaces Ω1 and Ω2 , respectively, with k1 and k2 measurable, and suppose we have random variables U ∈ H1 and Y ∈ H2 . [sent-97, score-0.198]

56 We define the conditional covariance operator ΣY Y |U on H1 by ˜ ΣY Y |U := ΣY Y − ΣY U Σ−1 ΣU Y . [sent-98, score-0.289]

57 UU (9) Corollary 2 easily yields the following result on the conditional covariance of variables: Theorem 3. [sent-99, score-0.233]

58 Let (Ω, B) be a measurable space, let (H, k) be a RKHS over Ω with k measurable and bounded, and let M be the set of all the probability measures on (Ω, B). [sent-107, score-0.24]

59 The following theorem can be proved using a argument similar to that used in the proof of Theorem 2 in [9]. [sent-109, score-0.065]

60 For an arbitrary σ > 0, the RKHS with Gaussian kernel k(x, y) = exp(− x− y 2 /2σ 2 ) on Rm is probability-determining. [sent-111, score-0.095]

61 Recall that for two RKHSs H1 and H2 on Ω1 and Ω2 , respectively, the direct product H1 ⊗H2 is the RKHS on Ω1 ×Ω2 with the kernel k1 k2 [6]. [sent-112, score-0.095]

62 The relation between conditional independence and the conditional covariance operator is given by the following theorem: Theorem 5. [sent-113, score-0.582]

63 Let (H11 , k11 ), (H12 , k12 ), and (H2 , k2 ) be RKHSs on measurable spaces Ω11 , Ω12 , and Ω2 , respectively, with continuous and bounded kernels. [sent-114, score-0.168]

64 Taking the expectation of the well-known equality VarY |U [g(Y )|U ] = EV |U VarY |U,V [g(Y )|U, V ] + VarV |U EY |U,V [g(Y )|U, V ] with respect to U , we obtain EU VarY |U [g(Y )|U ] −EX VarY |X [g(Y )|X] = EU VarV |U [EY |X [g(Y )|X]] ≥ 0, which implies Eq. [sent-120, score-0.082]

65 ⊥V From Theorem 5, for probability-determining kernel spaces, the effective subspace S can be characterized in terms of the solution to the following minimization problem: min ΣY Y |U , S 2. [sent-126, score-0.386]

66 (14) Kernel generalized variance for dimensionality reduction To derive a sampled-based objective function from Eq. [sent-128, score-0.365]

67 (14) for a finite sample, we have to estimate the conditional covariance operator with given data, and choose a specific way to evaluate the size of self-adjoint operators. [sent-129, score-0.289]

68 With a regularization ˆ constant ε > 0, the empirical conditional covariance matrix ΣY Y |U is then defined by ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ ˆ ΣY Y |U := ΣY Y − ΣY U Σ−1 ΣU Y = (KY + εIn )2 − KY KU (KU + εIn )−2 KU KY . [sent-135, score-0.233]

69 Using the A Schur decomposition, det(A − BC −1 B T ) = det B T B /detC, we have C ˆ ˆ ˆ det ΣY Y |U = det Σ[Y U ][Y U ] / det ΣU U , ˆ ˆ where Σ[Y U ][Y U ] is defined by Σ[Y U ][Y U ] = ˆ ˆ Σ Y Y ΣY U ˆ ˆ ΣU Y Σ U U = (17) ˆ ˆ ˆ (KY +εIn )2 KY KU ˆ ˆ ˆ (KU +εIn )2 KU KY . [sent-138, score-0.376]

70 ˆ We symmetrize the objective function by dividing by the constant det ΣY Y , which yields min m×r B∈R ˆ det Σ[Y U ][Y U ] , ˆ ˆ det ΣY Y det ΣU U where U = B T X. [sent-139, score-0.406]

71 (18) We refer to this minimization problem with respect to the choice of subspace S or matrix B as Kernel Dimensionality Reduction (KDR). [sent-140, score-0.159]

72 I(Y, U ), and with an entirely different argument, we have shown that KGV is an appropriate objective function for the dimensionality reduction problem, and that minimizing Eq. [sent-159, score-0.365]

73 Given that the numerical task that must be solved in KDR is the same as the one to be solved in kernel ICA, we can import all of the computational techniques developed in [9] for minimizing KGV. [sent-161, score-0.095]

74 To cope with local optima, we make use of an annealing technique, in which the scale parameter σ for the Gaussian kernel is decreased gradually during the iterations of optimization. [sent-163, score-0.095]

75 Next, we apply the KDR method to classification problems, for which many conventional methods of dimensionality reduction are not suitable. [sent-180, score-0.38]

76 In particular, SIR requires the dimensionality of the effective subspace to be less than the number of classes, because SIR uses the average of X in slices along the variable Y . [sent-181, score-0.5]

77 CCA and PLS have a similar limitation on the dimensionality of the effective subspace. [sent-182, score-0.303]

78 We show the visualization capability of the dimensionality reduction methods for the Wine dataset from the UCI repository to see how the projection onto a low-dimensional space realizes an effective description of data. [sent-184, score-0.53]

79 The Wine data consists of 178 samples with 13 variables and a label with three classes. [sent-185, score-0.073]

80 Figure 2 shows the projection onto the 2-dimensional subspace estimated by each method. [sent-186, score-0.195]

81 These results show that KDR successfully finds an effective subspace which preserves the class information even when the dimensionality is reduced significantly. [sent-197, score-0.462]

82 4 Extension to variable selection The KDR method can be extended to variable selection, in which a subset of given explanatory variables {X1 , . [sent-198, score-0.236]

83 Extension of the KGV objective function to variable selection is straightforward. [sent-202, score-0.116]

84 We have only to compare the KGV values for all the subspaces spanned by combinations of a fixed number of selected variables. [sent-203, score-0.104]

85 We of course do not avoid the combinatorial problem of variable selection; the total number of combinations may be intractably large for a large number of explanatory variables m, and greedy or random search procedures are needed. [sent-204, score-0.178]

86 We first apply this kernel method to the Boston Housing data (506 samples with 13 dimensional X), which has been used as a typical example of variable selection. [sent-205, score-0.155]

87 The selected variables are exactly the same as the ones selected by ACE [2]. [sent-207, score-0.109]

88 We select 50 effective genes to classify two types of leukemia using 38 training samples. [sent-209, score-0.206]

89 For optimization of the KGV value, we use a greedy algorithm, in which new variables are selected one by one, and subsequently a variant of genetic algorithm is used. [sent-210, score-0.08]

90 Half of the 50 genes accord with 50 genes selected by [12]. [sent-211, score-0.161]

91 With the genes selected by our method, the same classifier as that used in [12] classifies correctly 32 of the 34 test samples, for which, with their 50 genes, Golub et al. [sent-212, score-0.095]

92 5 Conclusion We have presented KDR, a novel method of dimensionality reduction for supervised learning. [sent-214, score-0.387]

93 essentially all existing methods for dimensionality reduction in regression, including SIR, pHd, CCA, and PPR. [sent-217, score-0.335]

94 We have demonstrating promising empirical performance of KDR, showing its practical utility in data visualization and feature selection for prediction. [sent-218, score-0.098]

95 The theoretical basis of KDR lies in the nonparametric characterization of conditional independence that we have presented in this paper. [sent-220, score-0.321]

96 Extending earlier work on the kernel-based characterization of marginal independence [9], we have shown that conditional independence can be characterized in terms of covariance operators on a kernel Hilbert space. [sent-221, score-0.762]

97 While our focus has been on the problem of dimensionality reduction, it is also worth noting that there are many possible other applications of this result. [sent-222, score-0.194]

98 In particular, conditional independence plays an important role in the structural definition of graphical models, and our result may have implications for model selection and inference in graphical models. [sent-223, score-0.341]

99 Nonlinear component analysis as a kernel eigenvalue o u problem. [sent-288, score-0.095]

100 Dimensionality reduction for supervised learning with reproducing kernel Hilbert spaces. [sent-309, score-0.364]


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